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What is the solution of log(2x + 6) 8 = 3?
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Is it x=-2?
(2x+6) is the base ?
Yes :)
\[\huge\color{blue}{ \log_{(2x+6)}8=3 }\] CLOSE ATTENTION ! \[\huge\color{blue}{ \log_{(2x+6)}8=3 }\huge\color{red}{ \times \log_{(2x+6)}(2x+6) } \] \[\huge\color{blue}{ \log_{(2x+6)}8=}\huge\color{blue}{ \log_{(2x+6)}(2x+6)^3 } \] \[\huge\color{blue}{ 8=(2x+6)^3 } \] see what I did and can do it from there ?
I think so! Would it be...
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Can you (to make sure) explain to me what I did in red ?
I think so! Would it be...\[2^3 = (2x+6)^3\]
Yep, good step!
I'm honestly not sure.. did you set it up so both sides equal each other?
yes, what I did in red is based on a rule \[\log_xx=1\]
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What is the rule called?
I don't remember.
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