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Mathematics 14 Online
OpenStudy (anonymous):

please check my work for these 1st derivative problems (: medal to the best answers!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

yep those are right

OpenStudy (anonymous):

no those aren't because I submitted them and a few sections came back wrong. for example for the 2x+7/x problem parts 3 and 4 are incorrect

OpenStudy (anonymous):

ok 1 min plz

OpenStudy (anonymous):

it is not 7/2 it is sqrt(14)/2

OpenStudy (anonymous):

ok better hurry pvt might beat you to it and my nipples are getting harder every second

zepdrix (zepdrix):

Were you able to figure these problems out ok? :)

OpenStudy (anonymous):

no :/

zepdrix (zepdrix):

Does it tell you which parts you got wrong by chance? :U

OpenStudy (anonymous):

well im limited on the number of attempts but i know for 2x+7/x problem parts 3 and 4 are incorrect

OpenStudy (anonymous):

so 69% of it is right ;)

zepdrix (zepdrix):

lol -_-

OpenStudy (anonymous):

for problem 5. 83% is right

zepdrix (zepdrix):

https://www.desmos.com/calculator/6jdvw8q2pm Look at the graph a sec. It might help you easily see where the function is increasing/decreasing.

zepdrix (zepdrix):

Where is the line `going up`? Just about everywhere except in the middle, right?

OpenStudy (anonymous):

right but 0,inf and -inf,0 don't work

zepdrix (zepdrix):

Mmmmm I'm not sure what you mean. It's increasing everywhere except in that tiny interval in the middle. It's increasing from (-inf, -sqrt(7,2))U(sqrt(7/2), inf) Does that make sense? :u

zepdrix (zepdrix):

By increasing I mean, f'(x) > 0

OpenStudy (anonymous):

yeah thanks for clarifying

OpenStudy (anonymous):

for part 4 is the decreasing function (0,4)? @zepdrix

zepdrix (zepdrix):

Mmmm yah that seems right! :)

OpenStudy (anonymous):

the interval includes two functions so im a bit unsure but it seems to make sense

OpenStudy (anonymous):

cool beans

zepdrix (zepdrix):

Oh oh there is an asymptote in there.. yahhh We might have to write it a little differently. my bad

zepdrix (zepdrix):

Where is the asymptote? x=2?

zepdrix (zepdrix):

(0,2)U(2,4) Something like that is needed I guess.

OpenStudy (anonymous):

that's correct, err its so easy to mess these problems up. I will persevere!

zepdrix (zepdrix):

Hehe good! :)

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