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Linear Algebra 8 Online
OpenStudy (anonymous):

prove that x^3-3x+3 is irreducible over Q of rational number

OpenStudy (loser66):

which course are you?

OpenStudy (tkhunny):

Rational Root Theorem seems the quickest way, no matter the course. The only Rational roots, if there are any, must be 1 or 3.

OpenStudy (loser66):

@tkhunny I would like to know the course in case it is required linear algebra proof. I mean proving based on the basis of P_3

OpenStudy (anonymous):

it is abstract algebra

OpenStudy (loser66):

oh yea!! that's what I think. hehehe... It's over my head. I am sorry.

OpenStudy (tkhunny):

I would be interested as well, but I'd still try the Rational Root Theorem, first.

OpenStudy (tkhunny):

Okay. x^3-3x+3 1) 3, a prime number, divides all the coefficients besides the first. 2) 3^2 = 9 does not divide the constant term. By the Eisenstein Criterion, this is irreducible in Q[x]. Seriously, why do it any hard way?

OpenStudy (anonymous):

he gives us hint that prove that it is irreducible over the integers, and use the lama ;let R a unique factorization domain,and let F be the filed of quotients foe R.Then if g(x)is irreducible over R[x] and F[x],then g(x0 is prime in R[x]

OpenStudy (tkhunny):

Well, okay, but if you use the Eisenstein Criterion, the rest of the class might throw things at you. It will be fun!

OpenStudy (anonymous):

3^2 = 9 does not divide the constant term. can u explain ?

OpenStudy (anonymous):

why u said 3^2?

OpenStudy (tkhunny):

It's the criteria. That's all. Ask Eisenstein. :-)

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