Question

How many milliliters of 0.149 M HCl would be required to titrate 5.58 g KOH?

Answer 1

Neutralization reaction:

HCl (aq) + KOH (aq) -> H2O (l) + KCl (aq)

Equal amounts of HCl and KOH neutralizes each other.

First calculate n (KOH) = m/M = n(HCl)

Then solve from equation n =cV volume V

0,149 M = 0,149 mol/l

You get volume in litres.