Question

If a windmill is connected to a hot water tank to heat 60.0 L of water from 12.0 C to 80 C , the energy required is ??

Answer 1

Use E=mc*change in T

Answer 2

in my class its Q=mcT so u mean find Q rigt?

Answer 3

Yerp

Answer 4

so 47137.5??

Answer 5

I got something else. Show me what you did.

Answer 6

250*45*4.19

Answer 7

right??

Answer 8

4.19 is the specific heat in J/gC so be sure to change your mass to grams. And what are the 45 and 250? O.o

Answer 9

250 g of caol and 45 the tempertaiure when u take the final temp- intial temp

Answer 10

O.o

Answer 11

can u do the hole thing and i will see if u get the right answer or not

Answer 12

It's just that your calculation doesn't sound anything like the question you posted.

Answer 13

Can you check if you're doing the right on or if your questions is right?

Answer 14

OMG yea ur right lol

Answer 15

so Q is 4120.8?

Answer 16

right??

Answer 17

No... Show your working again please.

Answer 18

60*68*1.01

Answer 19

whats wrong here?

Answer 20

60 L is 60 kg. 1.01 is not the specific heat capacity of water.

Note the units for the c you use.

Answer 21

damnn yea

Answer 22

ok what do i gdo after that??

Answer 23

Well you have to start over. Here:
We will use 4.186 joule/gram °C for the c. Note the unit is in joule, gram, and Celsius, so get the mass of water in grams.

Answer 24

17095.2

Answer 25

Here is the question, When 1 mole of urea undergoes combustion 632 KJ of energy are realesased.

2CO(NH2)2 + 7 O2............

The molar heat of dormation of urea is..??