Write a point-slope equation for the line that passes through the point (6, 8) and is parallel to the line given by y = -5x + 4
Well point slope is y - y1 = m( x - x1) For this you need to plug in (6, 8) into the equation along with the slope (m).
It gives you the slope because it says the slope is parallel to the line y = -5x + 4 This is line is in the format y = mx + b So since it is in this format, what number is in the place of "m"?
When you plug in the points it should look like this : y - 8 = m( x - 6) Do you know what the slope is?
im not sure... sorry
No no it's totally fine. Okay so slope is also referred to as "m". Slope intercept form is "y = mx + b" If I had an equation that was, say, y = 6x + 2. "6" would be in the place of "m". Are you following me?
yes i believe so...
Okay so it gives you a line already in the form y = mx + b. ( y = -5x + 4) So the slope in that line would be -5. Now that you have the slope, you can plug it into the equation y - 8 = m (x - 6) The 8 and the 6 come from the point (6, 8) in the problem.
You should get \[y - 8 = -5 ( x - 6 )\]
so its y-8=-5(x-6)?
yep :)
thank you so much :)
you're welcome!
Join our real-time social learning platform and learn together with your friends!