A particle’s position in meters is modeled as x(t) = 2^t * t^2, where t is greater than or equal to zero, and is measured in seconds. Find the velocity of the particle when t = 3 seconds.

48 ln 2
120
48 + 72 ln 2
48

Question

A particle’s position in meters is modeled as x(t) = 2^t * t^2, where t is greater than or equal to zero, and is measured in seconds. Find the velocity of the particle when t = 3 seconds.


	48 ln 2
	120
	48 + 72 ln 2
	48

whpalmer4 · Answer

Are you taking calculus?

anonymous · Answer

Yes.

whpalmer4 · Answer

Okay, do you know that velocity is the first derivative of position?

anonymous · Answer

So to solve this, I find the derivative of the given and then plug in 3 for t?

anonymous · Answer

48 + 72 ln 2
 would this be the answer?

whpalmer4 · Answer

Yep, that's what I get.  You could test this answer by evaluating x(3.01) and x(2.99), taking the difference and dividing by 3.01-2.99.  Should get a number very close to the value of 48 + 72 ln 2.