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Chemistry 10 Online
OpenStudy (anonymous):

Need help explaining Chemistry Unit 2 Lesson 10 Porfolio! MEDAL FOR BEST HELP!

OpenStudy (anonymous):

@wolfe8

OpenStudy (wolfe8):

Ok so what part do you need help with? Because the instructions are clear.

OpenStudy (anonymous):

Im have the hard time trying to sort out the number for question2

OpenStudy (anonymous):

@wolfe8

OpenStudy (wolfe8):

How did the experiment go?

OpenStudy (anonymous):

i still feel like i did i wrong but im not sure

OpenStudy (anonymous):

how much do i put for each of the solution again?

OpenStudy (wolfe8):

Number for what? In the solution column you just put in which of the 2 reactants you use is which.

OpenStudy (anonymous):

HCI and NaCI

OpenStudy (anonymous):

how mush do i put in>

OpenStudy (wolfe8):

I think that's the first one. The second one is 2NaOH + H2SO4 → Na2SO4 + 2H2O no? This is why it's hard to help with projects and labs because you're the one who does the lab. We can only guide you.

OpenStudy (anonymous):

oh ok so2NaOH + H2SO4 → Na2SO4 + 2H2O is #2 than what do i leave in the chart?

OpenStudy (anonymous):

im srry im taking your time on this, i really thank you for helping me

OpenStudy (wolfe8):

Well which one is the base which one is acid? Molar ratio can be obtained just by looking at the balanced equation; take a look under the equation.

OpenStudy (anonymous):

naoh is the base and hci is the acid i believe

OpenStudy (wolfe8):

Well again, are you asking for the first one or second one?

OpenStudy (anonymous):

omg im lost now

OpenStudy (chmvijay):

lol :P

OpenStudy (anonymous):

ok lead me thoug the first one then i have me understand better

OpenStudy (wolfe8):

Ok well look at the end of your fourth page. Those are your equations for questions 1 and 2 if I understand correctly. Only you will know for sure since YOU'RE the one who did the lab. So now for the first one you will decide which is which from the first equation.

OpenStudy (anonymous):

the first one

OpenStudy (wolfe8):

Yes

OpenStudy (anonymous):

and the second one is for the second problem

OpenStudy (anonymous):

got it! and what do i leave in the chart?

OpenStudy (wolfe8):

Yes

OpenStudy (anonymous):

^ I I

OpenStudy (wolfe8):

Like I said, in the solutions column which is which. Molar ratio is given.

OpenStudy (anonymous):

below the answer for the first qutsion said "mole ratio of acid to base is 1:1"

OpenStudy (wolfe8):

Hmm wait. Mole ratio and molar ratio are different. Molar is the concentration in moles/L. What concentration did you use?

OpenStudy (anonymous):

mine said unknown M

OpenStudy (anonymous):

yeah , i didnt do it right :/

OpenStudy (wolfe8):

What info DO you have? This is really hard for me to explain to you from my side :/

OpenStudy (anonymous):

this is what i hvae

OpenStudy (anonymous):

@wolfe8

OpenStudy (wolfe8):

Ok so you have the concentration for NaoH. You can find concentration for HCl using the method on page 3.

OpenStudy (anonymous):

but shouldnt my concentration be 0.1?

OpenStudy (anonymous):

@wolfe8

OpenStudy (wolfe8):

I don't know. You'll have to use the final volumes at the end of the titration

OpenStudy (anonymous):

how did you get it?

OpenStudy (wolfe8):

You do the lab till the end...

OpenStudy (anonymous):

D:: the fustration

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