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Solve ln(5x+5)=2 round to the nearest thousand??
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Raise both sides to \(e\): \[e^{\ln(5x+5)} = e^2\]Do you know what happens when you have \(e^{\ln(x)}\)?
Nice name @Richard_Feynman and explanation :)
@Richard_Feynman no
The natural log will give you the power you have to raise e to in order to get a particular value, so if you raise e to the power that you have to raise e to to get \(5x+5\), it's going to equal \(5x+5\), i.e. \(e\) cancels out \(\ln\).
So from the above equation, you can turn it into \[5x+5 = e^2\]
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so then do you devide everything by 5? @Richard_Feynman
Most people would subtract 5 before dividing but you can do it either way.
You should end up with \(x = \frac{e^2}{5} - 1\).
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