Question

Find the derivative of..

Answer 1

\[\LARGE y= sinh(coshx)\]

Answer 2

Do you know the product rule?

Answer 3

I do, but hmm you sure it would be used here?

Answer 4

read that wrong

Answer 5

Chain rule?

Answer 6

So just to verify.. it would be
\[\LARGE y'=sinh*cosh(cosh~x)\]
Right? Seems a bit simple

Answer 7

Just wasn't sure ._.

Answer 8

That's correct.

Answer 9

yea, I concur

Answer 10

Alright, thanks guys!

Answer 11

Just make sure you write sinh(x) not sinh. Just a typo I'm sure.

Answer 12

^yes second that from Kainui

Answer 13

Whoops, forgot my x >.<

Answer 14

\[\sinh x=\frac{ e^{x}-e ^{-x} }{ 2 }\]

Answer 15

it happens

Answer 16

\[coshx=\frac{ e^x+e^-x }{ 2 }\]

Answer 17

can u solve it now

Answer 18

^That doesn't really help here g17, that would be one nasty x value

Answer 19

@FibonacciChick666
thn u can not differentiate it

Answer 20

u have to use these values

Answer 21

it's just chain rule @g17

Answer 22

yeah

Answer 23

sub u=cosh x du=sinhx then solve

Answer 24

but the sub like that would be nasty

Answer 25

but should know first wat is the value of sinh or cosh

Answer 26

i mnot saying to substitue loll
first differ.. nd thn put the valuesloll

Answer 27

oh, I thought you were implying subbing the e^x forms

Answer 28

You don't even need that definition for this problem though