d/dx logx
Maybe you can try to differentiate it by first principle.
\[f'(x) = \lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}\]
you could, depends on the base though
Some time ago, my teacher told me when we did higher math, "log" you saw would be the natural log, i.e. "ln" If it is log in base 10, you can do the conversion:\[\log x = \frac{\ln x}{\ln 10}\]
Solving this question by the first principle is not so easy though.
i asked u what is deivative of log x the answer is 1/x for this what all stupidity u r saying
I know the answer, but I can't directly tell you the answer.
y
Code of Conduct of this site: "Give Help, Not Answers - I will encourage and guide those needing help, and not just give them an answer" Ref: http://openstudy.com/code-of-conduct
Also, @FibonacciChick666 just raised his/her concern about the base of log in your question. If it was in base 10, then the answer would not be 1/x.
or base 2,
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