Question

-3≤2x+1<7

Answer 1

subtract "1" thru out

Answer 2

-3≤2x+1<7
-1 -1 -1

Answer 3

-4≤2x<6

Answer 4

any idea what needs to be done next ?

Answer 5

it needs to be simplified fully

Answer 6

yup, the goal is to isolate "x" by itself

Answer 7

Since "2" is attached to "x", divide "2" thru out

Answer 8

-4≤2x<6
/2 /2 /2

Answer 9

wat wud u get ?

Answer 10

-2,-1,3

Answer 11

not quite,

Answer 12

-2≤x<3

Answer 13

so, the solution is :-

x can be greater than or equal to -2, and less than 3

Answer 14

thanks. please sove 3x-7<-13 x C R for me

Answer 15

is it like below :-

\(3x-7 \lt -13\)

Answer 16

?

Answer 17

is it now solved?

Answer 18

nope, i am asking whether the given inequality was like that ? :)

Answer 19

yes

Answer 20

okay, to solve it, u need to isolate "x"

Answer 21

\(3x-7 \lt -13\)

Answer 22

start by adding "7" both sides

Answer 23

that will be 10x-5

Answer 24

ahh i see wat u did there,
but the thing is we cannot add coconuts and oranges

Answer 25

we cannot add "3x" and "7" okay ?

3x and 7 wont produce 10x

Answer 26

\(3x-7 \lt -13\)

add "7" both sides

\(3x-7 \lt -13\)
+7 +7

\(3x\lt -6\)

Answer 27

you wud get that,
cuz 7 and -7 cancel out on left side

Answer 28

next, dividing "3" both sides isolates "x" fully

Answer 29

so, divide "3" both sides

Answer 30

\(3x\lt -6\)
/3 /3

\(x < -2\)

Answer 31

since "x" is fully isolated, we're done.
above is the solution; in words it is : x less than -2

Answer 32

thanks so much, i have followed but i need more practice

Answer 33

good, and yes... doing 2-3 more problems like this will make u confident :)

Answer 34

any recommendation for reading material(s)

Answer 35

https://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities/equations_beginner/v/simple-equations

Answer 36

i find those videos and examples are good... give it a try :)

Answer 37

@mukarori I think it will be beneficial to you to always remember the key objective in this exercise, to isolate x. Also do not forget that to do this effectively you need to have a strong understanding in inverse operations (i.e. The inverse of addition is subtraction) and also keep in mind that variables are not interchangeable, they are set to what they are and cannot be added freely (i.e. 1x cannot be added to 5y). Hope this helps! Don't forget to always practice :D

Answer 38

@JA1 thanks so much

Answer 39

^^thats a good piece of advice.. samething in my head :)

Answer 40

No problem, glad to help :)