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Mathematics 22 Online
OpenStudy (anonymous):

Help with Math..? Will give Medal.

OpenStudy (anonymous):

Water coming out from a fountain is modeled by the function f(x) = -x2 + 6x + 6 where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds. The water travels an average distance of 4 feet from 2 seconds to 5 seconds. The water travels an average distance of 1 foot from 2 seconds to 5 seconds. The water falls down with an average speed of 2 feet per second from 2 seconds to 5 seconds. The water falls down with an average speed of 1 foot per second from 2 seconds to 5 seconds.

OpenStudy (anonymous):

I know the solution to f(x) = -x2 + 6x + 6 will be -1. But I don't know what the answer is.

OpenStudy (anonymous):

I think it's D.

OpenStudy (anonymous):

@amistre64 Can you check my answer?

OpenStudy (radar):

If it is D, then at 2 seconds it is f(x)=-x^2+6x+6=-(2^2) + 6(2) + 6=14 ft. then at 5 seconds it is -(5^2) +(5)^6) +6 =-25 +30 + 6 = 11 ft (14-11)ft/(5-2)sec= 3/3 ft/sec - 1 ft/sec

OpenStudy (anonymous):

So I was right..?

OpenStudy (anonymous):

No wait, I was wrong.

OpenStudy (amistre64):

i believe average is the slope of the line between a stated interval

OpenStudy (anonymous):

The slope between the two lines would be -5/3, right?

OpenStudy (anonymous):

No wait, -3/3

OpenStudy (anonymous):

Which would give us -1

OpenStudy (amistre64):

slope between the 2 points ... an average speed is the slope, an average distance i want to say is displacement

OpenStudy (amistre64):

too early to think in circles :)

OpenStudy (anonymous):

Right, I get it. So you're saying that the distance between x = 2 and x = 5 has a slope of -1.

OpenStudy (amistre64):

yes, so the average speed would be defined by the slope

OpenStudy (anonymous):

So the answer is B?

OpenStudy (anonymous):

Oh wait, he said average speed, so the answer IS D.

OpenStudy (anonymous):

@radar Could you help with another?

OpenStudy (anonymous):

What is the domain of the following parabola? All real numbers x ≥ 1 x ≤ 2 y ≥ -3 I think it's A.

OpenStudy (radar):

I might, but you did see how you can check your answer .

OpenStudy (anonymous):

Yes, I did.

OpenStudy (anonymous):

I think it's A because the parabola goes on forever..

OpenStudy (radar):

I get confused on range and domain

OpenStudy (anonymous):

Domain = all x values Range = all y values I get confused on them too :l

OpenStudy (radar):

You know you may be right even though big values of x will take a long time to get there, Looking a B, we see x can equal 0 so that is out. I thank C is out as we can se x can = 2 Obviously D is out as y goes to high values, thru the process of elimination I would say you are correct.

OpenStudy (anonymous):

Oh, okay.

OpenStudy (radar):

Yes, I would say of those choices A is the best answer, good luck with those thing.

OpenStudy (anonymous):

I have one more, this is it: The table below shows the values of f(x) and g(x) for different values of x. One of the functions is a quadratic function and the other is an exponential function. Which function is most likely increasing quadratically? x f(x) g(x) 1 2 2 2 5 4 3 10 8 4 17 16 5 26 32 f(x) because it grows slower than g(x) f(x) because it eventually intersects g(x) g(x) because it grows faster than f(x) g(x) because it will not intersect f(x) I chose A, because I think g(x) is the exponential function and f(x) is the quadratic function. And I know that exponential functions will eventually intersect and grow more than quadratic functions. So I think it's A because f(x) is slower than g(x) because it will eventually grow less than g(x).

OpenStudy (anonymous):

It could be A, because f(x) does grow slower than g(x). It can't be B, because f(x) will not eventually intersect g(x), it's the other way around. It cannot be C, because it's asking what is the quadratic function, not what is the exponential one. It couldn't be D, because they DO intersect each other.

OpenStudy (radar):

I am puzzled by this I graphed two functions one being x^2, the other being 2^x and the 2^x eventually reached higher values than the x^2, so it looks like the g(x) is a exponential function, as far as intersection is concerned that doesn't help me as both graphs would have to cooperate to intersect. I am inclined to go with your reasoning. This is new ground for me.

OpenStudy (anonymous):

So you're saying that f(x) is the exponential one, instead of g(x)?

OpenStudy (radar):

No i said I think the 2^x (expotential) was the fastest growing, thus the quadratic was the slower as you also surmised.

OpenStudy (anonymous):

Ah, thank you so much.

OpenStudy (anonymous):

They were all correct.

OpenStudy (radar):

You're welcome, good luck with your studies. I gotta go now for breakfast.

OpenStudy (anonymous):

Enjoy!

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