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Mathematics 13 Online
OpenStudy (anonymous):

a

OpenStudy (fibonaccichick666):

So for the first person, Does the day of the year matter?

OpenStudy (fibonaccichick666):

or does it only matter for the other two

OpenStudy (fibonaccichick666):

no, that's actually me answering haha

OpenStudy (fibonaccichick666):

I like you to think through the problem

OpenStudy (fibonaccichick666):

so, for the first person. Assuming it is not a leap year, what is the probability that they were born on a day of the year?

OpenStudy (fibonaccichick666):

not quite

OpenStudy (fibonaccichick666):

The first probability is what is wrong,

OpenStudy (fibonaccichick666):

the method is correct

OpenStudy (fibonaccichick666):

yup np, do you understand why it's \(\frac{1}{1}\)?

OpenStudy (fibonaccichick666):

good!

OpenStudy (fibonaccichick666):

Well done

OpenStudy (anonymous):

(1/365)^3 actually the probability of three people having a same PARTICULAR birthday. E.g March 19. But since it could be any day of 365 days, what you should have done is 365 * (1/365)^3, and this will give you the right answer

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