Question

The angle bisectors of XYZ intersect at point A, and the perpendicular bisectors intersect at point C. AB_XZ What is the radius of the inscribed circle of XYZ?

Answer 1

@eliassaab are you on?

Answer 2

i need to find it in units

Answer 3

It is 10.3
let me explain why

Answer 4

AYZ is isoceles
Hence XYZ is isoceles, therefore XA is perpendicular to YZ. This implies that C is on the bissector of YXZ. That shows that C , A nad X are on he same line. Hence CX is the radius
CX =CA +AX = 3.3 + 7= 10.3

Answer 5

thats not one of my choices

Answer 6

the radius of the inscribed circle XYZ
3.3
4.5
7
9
11

Answer 7

I misread the question. I found the radius of the circumscribed circle. Hold on

Answer 8

The center of it is A and the radius is AB=4.5

Answer 9

what is the formula for that?

Answer 10

XYZ=

Answer 11

9

Answer 12

The center is the intersection of the 3 bisectors. So A is the center. The radius is
the distance from A to any of the three sides which are all equal. In this case, we are given one of the distances AB=4.5

Answer 13

So its that simple?

Answer 14

The rest was given to confuse the situation.

Answer 15

I know how to find the radius and I don't know why I was so thrown off. Well they did a good job at confusing me. Thank you!!!!

Answer 16

@eliassaab how did you find the radius of the circle circumscribing the triangle?

Answer 17

The center is the intersection C of the perpendicular bisectors. The radius is
CX=CY=CZ

Answer 18

Oh..how stupid of me! Thanks anyways! :D