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Chemistry 13 Online
OpenStudy (anonymous):

How is 2 Mg(s) + O2(g) → 2 MgO(s) unbalanced?

OpenStudy (anonymous):

Because you have two oxygens

OpenStudy (anonymous):

on the reactant side

OpenStudy (anonymous):

Wait

OpenStudy (anonymous):

There is a 2 on the product side that essentially distributes to the O making it have 2 oxygens too

OpenStudy (anonymous):

What makes you think it's unbalanced because it is balanced

OpenStudy (anonymous):

I know that it is balanced in the sense that there is an equal amount of elements on each side. I'm supposed to find and think about all ways the equation is balanced and is unbalanced. I've been racking my brain trying to think of ways it could be unbalanced, but I'm not very good at stoichiometry or calculating moles, mass, energy change, reaction rates, etc. So I'm not sure how to find any way it isn't balanced.

OpenStudy (anonymous):

The thing I think makes it unbalanced is the (g) and (s)

OpenStudy (anonymous):

Because everything else besides those is all balanced

OpenStudy (anonymous):

But would just having different states of matter be a reason to say it is "unbalanced"? That was the only thing I could think of too but I'm not really sure why it would be unbalanced just because of that.

OpenStudy (anonymous):

Well actually

OpenStudy (anonymous):

I think I know why now

OpenStudy (anonymous):

Why?

OpenStudy (anonymous):

Wait nvm

OpenStudy (anonymous):

I really am positive that this is balanced

OpenStudy (anonymous):

I would ask your teacher about this, it may be a mistake.

OpenStudy (anonymous):

Okay. Thanks for your help :) Do you think the energy of it is all balanced too?

OpenStudy (anonymous):

It's all balanced

OpenStudy (anonymous):

I dont know what you mean by energy, but when it comes to balancing

OpenStudy (anonymous):

Every side has to have the same amount of elements.

OpenStudy (anonymous):

Just keep practicing, I remember I had a little trouble with balancing equations with some practice I finally got it.

OpenStudy (anonymous):

Message me if you ever need help, and I'll gladly help you :D

OpenStudy (anonymous):

Okay thanks a ton again :) Will do. :)

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