Help please
Wendy is looking over some data regarding the strength of some rope and how that relates to its number of woven strands. The data seem to be exponential. How can Wendy determine if the data are exponential, and how can she convert that to a logarithmic function?

Question

Help please 
Wendy is looking over some data regarding the strength of some rope and how that relates to its number of woven strands. The data seem to be exponential. How can Wendy determine if the data are exponential, and how can she convert that to a logarithmic function?

anonymous · Answer

@Opcode @KingGeorge @abb0t @wolfe8

anonymous · Answer

Pleas help me If I fail this I will go below my grade.

ganeshie8 · Answer

say "y" is strength,
and "x" is number of woven strands

anonymous · Answer

k please do this step by step so ic an take notes

anonymous · Answer

help me ganeshie8 I em bigpapa021201

anonymous · Answer

please hes helping me first

anonymous · Answer

pleas leave

anonymous · Answer

okay

anonymous · Answer

@ganeshie8 please continue

anonymous · Answer

@ganeshie8 ??

anonymous · Answer

i will help you

anonymous · Answer

Well, Yayo, I'd start with an exponential model based upon the most basic exponential function, y = e^x.
Then I'd modify this function by inserting a constant coefficient, k.
Then I'd take a couple of points (which I hope you have) and substitute the x and y values for each point into this model:  y = ke^x.
If you can determine a value k that makes the equation true for all of your data points, then lo and behold, the data are exponentially related.  Please try it.

anonymous · Answer

you just coppied an answer thanks bt no thanks I need @ganeshie8

anonymous · Answer

okay

ganeshie8 · Answer

For the data to be exponential, the strength needs to increase very rapidly as the number of woven strands increase, and it needs to follow below equation form :-

$y = Ae^x$

ganeshie8 · Answer

sorry, my browser crashed...

anonymous · Answer

ohh its okay okay whats next?

ganeshie8 · Answer

@bigpapa021201  after this, il come to ur thread :)

anonymous · Answer

okay thank you

ganeshie8 · Answer

$y = Ab^x$

to convert it to logarithmic function, take "log" both sides :

$\log (y) =   \log (Ab^x)$

By using product property, log of products equals sum of logs :

$\log (y) =   \log (A) + \log (b^x)$

ganeshie8 · Answer

this is a logarithm function now !

note that i have changed "e" to "b", just to be more generic

anonymous · Answer

okay

ganeshie8 · Answer

we're done

ganeshie8 · Answer

see if that makes some sense.... let me knw if smthng doesnt :)

anonymous · Answer

okay I get it so this would be the answer corretc Ill put it the way i understood it

ganeshie8 · Answer

yup, just replace the initial "e" wid "b"

ganeshie8 · Answer

the exponential function is :  $y = Ab^x$

ganeshie8 · Answer

its not $y = Ae^x$

okay ?

anonymous · Answer

yea i get it thanks :)

anonymous · Answer

I have another question but

ganeshie8 · Answer

shoot

anonymous · Answer

@amistre64 do you know if the formula $$y = a b^{x}$$ is correct?

amistre64 · Answer

its hard to parse thru a 3 month old question, can you ask your question anew?

amistre64 · Answer

a log function is not exponential ... but that may be a step in getting a log function simply by inverse

anonymous · Answer

what exactly do you mean by that?

anonymous · Answer

HELP! @amistre64

amistre64 · Answer

i mean, instead of asking your question in some outdated thread, use the 'ask a question' box to type in your own question.

this one is simply to outdated to for me to focus on any train of thought that may have transpired.

anonymous · Answer

@amistre64 I tagged you in a new post