Question

Calculate the ratio of effusion rates for methane and nitrogen

Answer 1

The effusion of pure methane gas (CH4) is 47.8 mL/min and nitrogen is 40 mL/min.

Answer 2

The ratio for effusion rates for methane and nitrogen most set up as:
\[\Large Q _{rate}=\frac{ rate _{CH _{4}} }{ rate _{N _{2}} }\]
Here is \(Q_{rate}\) the ratio, and the rates are temperature dependent. You can show from chemical dynamics and molecular motion that the ratio for effusion rates are given by
\[\Large Q _{rate}=\frac{ rate _{CH _{4}} }{ rate _{N _{2}} }=\sqrt{\frac{ M(N _{2}) }{ M(CH _{4)} }}\]
This law is also known as Graham's law of effusion.

You can show the equations validation and assumptions by deriving it from Knudsen effusion method.

@Ria23 your method is correct, but your numbers need to be at the same temperature \(T\). If they are you can calculate the ratio from the numbers, else the answer is incorrect.