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Mathematics 8 Online
OpenStudy (anonymous):

simplify: equation is in the answer box please help me

OpenStudy (anonymous):

\[\frac{ 1 }{ \cos \theta }=\frac{ \sin2\theta \cos \theta- \cos2 \theta \sin \theta }{ \sin \theta \cos \theta }\]

OpenStudy (amistre64):

hmmm, it just algebra .. you either want to solve for theta, or show that this is an identity?

OpenStudy (amistre64):

use the double angle identities to pull apart those 2thetas into sin cos parts that can be canceled or worked with better

OpenStudy (anonymous):

It's a proof, amistre64.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

can u solve it?

OpenStudy (anonymous):

please help me

OpenStudy (anonymous):

I can help you solve it. Do you have a sheet with all of the trig identities on it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

And you understand that you have to change things on the more complicated side in order to reach the other side of this right?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Okay, so, double angles. What formulas do you have for those?

OpenStudy (anonymous):

\[\sin 2 \theta = 2 \sin \theta \cos \theta\]

OpenStudy (anonymous):

\[\cos 2 \theta = \cos ^{2} - \sin ^{2} = 1 - 2\sin^{2}\theta = 2\cos^{2} \theta -1\]

OpenStudy (anonymous):

i have other ones but they dont really apply

OpenStudy (anonymous):

So first I think you should change the sin2theta, on the left hand side, to the first formula you gave me

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I'm working on this :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Okay, this is all solved out. So what happens when you plug in that sin property?

OpenStudy (anonymous):

Also, you're going to use the (cos^2theta-sin^2theta) for the cos2theta

OpenStudy (anonymous):

Write that out and post it for me

OpenStudy (anonymous):

i can only cancel out the cos (theta)

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

|dw:1395030731423:dw| You can cancel the sins

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