simplify: equation is in the answer box please help me
\[\frac{ 1 }{ \cos \theta }=\frac{ \sin2\theta \cos \theta- \cos2 \theta \sin \theta }{ \sin \theta \cos \theta }\]
hmmm, it just algebra .. you either want to solve for theta, or show that this is an identity?
use the double angle identities to pull apart those 2thetas into sin cos parts that can be canceled or worked with better
It's a proof, amistre64.
thanks
can u solve it?
please help me
I can help you solve it. Do you have a sheet with all of the trig identities on it?
yes
And you understand that you have to change things on the more complicated side in order to reach the other side of this right?
yeah
Okay, so, double angles. What formulas do you have for those?
\[\sin 2 \theta = 2 \sin \theta \cos \theta\]
\[\cos 2 \theta = \cos ^{2} - \sin ^{2} = 1 - 2\sin^{2}\theta = 2\cos^{2} \theta -1\]
i have other ones but they dont really apply
So first I think you should change the sin2theta, on the left hand side, to the first formula you gave me
ok
I'm working on this :)
ok
Okay, this is all solved out. So what happens when you plug in that sin property?
Also, you're going to use the (cos^2theta-sin^2theta) for the cos2theta
Write that out and post it for me
i can only cancel out the cos (theta)
hello
|dw:1395030731423:dw| You can cancel the sins
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