Question

A slow leak in a water pipe develops in such a way that on the first day of the leak, one ounce of water drips out. Each day thereafter, the amount of water lost is one-half once more than the day before. How many ounces of water will leak out in 60 days?

Answer 1

on first day, 1 ounce, on the next 1.5.... so there is an increase of 0.5 drops everyday.
So
the progression you can make is
1, 1.5, 2, 2.5, 3, 3,5 and so on...
The sum of this progression till n = 60 would be
n/2(2a+(n-1)d)
hence its 30*(2+(59*0.5))
which is 945.
So 945 ounces :)
cheers :D

Answer 2

thnx..:)

Answer 3

Mathbreaker got it.

Answer 4

And it was simpler. But a recursive function would have worked as well.

Answer 5

Haha yeah i did, took me a while i was about to do 0.5^60 hehe....

Answer 6

Haha i wish i knew what recursive functions were :P

Answer 7

I was doing a recursive function. Would have been hell. But series are like that.

Answer 8

x_1 = 1
x_n = x_(n-1)+.5

Answer 9

Wow that wouldve taken a while :P
For me atleast haha