Cookies (c) and bottles of water (w) are sold at a snack bar. The cost of 4 cookies and 2 bottles of water is $3.90 before tax. The cost of 3 cookies and 3 bottles of water is $4.05 before tax.
here
so wat r u asking
What's your question...?
where is the rest of the problem?
oh, sorry hold on
thats fine
a) Write the systems of equations that represent the information b) Use the system of equations to determine the cost of 1 cookie and the cost of 1 bottle of water before tax
okay let me see
@Mathbreaker
take ur time
so its 4c + 2w = 3.9 3c + 3w = 4.05 solve these equations to get teh answer :) Simultaneous equations :)
okay 4c+2w=$3.90
c4+2w=3.90 w~~0.5 (3.9-c^4)
c = 0.6 and w = 0.75 just in case youre confused :)
Therefor w is simply fifty cents
ya I kinda was lol, I kinda suck at math
thx guys, so jsut to be sure the answer is $.50
*just
Haha its all about practice i bet you dont :) Look up simultaneous answers if you want help with that No i dont think so, i solved it on wolfram alpha and got http://www.wolframalpha.com/input/?i=4c+%2B+2w+%3D+3.9%3B+3c+%2B+3w+%3D+4.05 Im too lazy to do the math but i think tits 0.6 and 0.75
ok thx!
Yeah wolfram's my rock.
c4+2w=3.90
Emilyowl, its not c^4.. its 4c + 2w = 3.9 this isnt an exponential function its simply simultaneous :)
its not c4 guys! Its 4*c + 2*w = 3.9 c4 would be c * c*c*c.... thats weird :P
Ill give you a final answer 4c + 2w = 3.9 3c + 3w = 4.05 Solving them simultaneous according to this link: http://www.wolframalpha.com/input/?i=4c+%2B+2w+%3D+3.9%3B+3c+%2B+3w+%3D+4.05 Gives me c = 0.6, w = 0.75. And i am absolutely certain its right.
If you were to use c as a real number hypothetically, then the problem would be exponential.
What are you implying emilyowl? That makes no sense. Its not exponential. its a system of equations, thats simultaneous :|
I'm not implying anything, what I said is what I've learned. But it doesn't really matter anymore so okay.
haha alright im confused about why you put c^4, but lets leave it at this haha
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