A class has 20 students of which 12 are females and 8 are males. In how many ways can a committee of 5 students be picked from this class if no males are to be included in the committee?

Question

anonymous · Answer

So really the number of 8 male students is useless

anonymous · Answer

12*11*10*9*8 = ?
After every student is picked she cant be picked again. And there are 5 member is the committee.

anonymous · Answer

So a female student cant be picked twice?

anonymous · Answer

Pretty sure only 1 person can be running for a position.

anonymous · Answer

hmmm

anonymous · Answer

Well I think of it as there are 12 possible people to do this and only 5 to a group so I set it up as 12*5=

anonymous · Answer

its 60 from what I am guessing

anonymous · Answer

I get 94050

anonymous · Answer

95040

anonymous · Answer

No thats obviously too much xD

anonymous · Answer

That is each possible combination that we can have. 60 is too little.

anonymous · Answer

If there has to be atleast one different student in each group its 60 but if they have to be in different positions every time then you could do what I did with numbers 1, 2, 3, 4, 5 
then 2, 1, 4, 5, 3 etc

anonymous · Answer

But still we are talking about 12 girls maybe if we added them instead of multiplying