You roll two dice. Let event A be "The first die shows a 2, a 3, or a 5" and event B be "The second die shows an odd number." What is P(A|B)?

A. 1/3
B. 1/2
C. 5/6
D. 1/6

Question

You roll two dice. Let event A be "The first die shows a 2, a 3, or a 5" and event B be "The second die shows an odd number." What is P(A|B)?

 		A.	1/3
 		B.	1/2
 		C.	5/6
 		D.	1/6

turingtest · Answer

$$P(A|B)={P(A\cap B)\over P(B)}$$what is the $P(A\cap B)$, which is the probability that both events occur?
what is $P(B)$, the probability that the second die shows an odd number?

anonymous · Answer

I have no idea

turingtest · Answer

take into consideration whether these are independent events as well, that will dramatically simplify your calculation

turingtest · Answer

does rolling one die have an effect on the other?

anonymous · Answer

No

turingtest · Answer

so then, by the definition of independence, $P(A\cap B)=P(A)P(B)$so then what does the expression for $P(A|B)$ become?

anonymous · Answer

total no. of exhaustive events=6*6=36
favourable events are {21,23,25,31,33,35,51,53,55}
no. of favourable events=9
P=?
i don't know where i am wrong.