Find the equation of the line. parallel to the x-axis, passing through (3,-6)
it is parallel to the x-axis, so it will look like this: |dw:1394817076995:dw| the \(line\ will\ always\ pass\ through\ \large{y=-6}\), since it is parallel to the x-axis. therefore the equation will be..?
wait
it also needs to include the formula: y=m(x-p)+q
sorry i forgot to mention that...
and by "it" i mean like the whole question
parrallel to x axis means line has slope =0
since it is \(parallel\ to\ the\ x-axis\), the slope(m) will be 0 \(y= 0(x-p)+q\\y=0(x-3)-6\\ y= ? \)
so standard equation y=mx+c with slope =0 y=c
so put the given point in equation as no x term in equation ..so just plugged in the y value and calculate value of C
-6=c so c=-6 as y=c=-6 so y=-6
ok what i've picked up is.. m=0 (p,q)=(3,-6) y=0(x-3)-6
whats next..?
0x-3-6 right?
loll 0*x-0*3-6
y=0-0-6
|dw:1394817775494:dw|
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