Find the equation of the line.
parallel to the x-axis, passing through (3,-6)
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OpenStudy (anonymous):
it is parallel to the x-axis, so it will look like this: |dw:1394817076995:dw|
the \(line\ will\ always\ pass\ through\ \large{y=-6}\), since it is parallel to the x-axis.
therefore the equation will be..?
OpenStudy (shelby1290):
wait
OpenStudy (shelby1290):
it also needs to include the formula: y=m(x-p)+q
OpenStudy (shelby1290):
sorry i forgot to mention that...
OpenStudy (shelby1290):
and by "it" i mean like the whole question
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OpenStudy (anonymous):
parrallel to x axis means line has slope =0
OpenStudy (anonymous):
since it is \(parallel\ to\ the\ x-axis\), the slope(m) will be 0
\(y= 0(x-p)+q\\y=0(x-3)-6\\ y= ? \)
OpenStudy (anonymous):
so standard equation
y=mx+c
with slope =0
y=c
OpenStudy (anonymous):
so put the given point in equation
as no x term in equation ..so just plugged in the y value and calculate value of C
OpenStudy (anonymous):
-6=c
so c=-6
as y=c=-6
so y=-6
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OpenStudy (shelby1290):
ok what i've picked up is..
m=0 (p,q)=(3,-6)
y=0(x-3)-6
OpenStudy (shelby1290):
whats next..?
OpenStudy (shelby1290):
0x-3-6
right?
OpenStudy (anonymous):
loll
0*x-0*3-6
OpenStudy (anonymous):
y=0-0-6
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