The graph of f (in blue) is translated a whole number of units horizontally and vertically to obtain the graph of h (in red). The function f is defined by f(x)= sqrt x Write down the expression for h(x)
\[y = f(x)+a\]is the graph of \[y = f(x)\]shifted vertically by \(a\) units \[y = f(x-a)\] is the graph of \[y = f(x)\]shifted horizontally by \(a\) units
That's not right. It's -4 and it's in the square root,
ive been working on this since yesterday and it still isn't any clearer. ive also been reading other pieces of information on transformations.
can someone give me the solution and tell me why it works? I have like 12 more of these.
look at the graph, for definiteness, pick one point : the thick solid point.
on blue graph, it is at (0, 0) on red graph, it is at (4, 2) right ?
that means the point (0, 0) shifted to the point (4, 2) : (0, 0) ---> (4, 2)
it seems, x values are shifting "right" by 4 units, and y values are shifting "up" by 2 units
would it be: \[f(x)=\sqrt{x-4}+2\] @ganeshie8
It would be. Just like I advised you initially: \[f(x-4) + 2\]to shift horizontally by 4 and vertically by 2
what happens to the radical?
never mind I get it it goes under the radical. thank you..
The radical is still there. \[f(x) = \sqrt{x}\]\[f(x)+a = \sqrt{x}+a\]\[f(x-a) = \sqrt{x-a}\]
and \[f(x-a)+b = \sqrt{x-a}+b\]
think of \[f(x) = \sqrt{x}\]as a recipe. It means "whenever you see the expression \(f(expression)\), replace it with \(\sqrt{expression}\)"
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