Mathematics
7 Online
OpenStudy (anonymous):
Simplify:
(−12x^3y^4 + 6x^2y^2) ÷ 6x^2y^2
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{−12x^3y^4 + 6x^2y^2}{6x^2y^2}\)
ganeshie8 (ganeshie8):
start by factoring the GCF from numerator
ganeshie8 (ganeshie8):
and see if something cancels away wid the denominator
OpenStudy (anonymous):
I thought I could cancel out both 6x^2y^2
ganeshie8 (ganeshie8):
yes !!
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{−12x^3y^4 + 6x^2y^2}{6x^2y^2}\)
factor out 6x^2y^2 in numerator
\(\large \frac{6x^2y^2(−2xy^2 + 1)}{6x^2y^2}\)
ganeshie8 (ganeshie8):
now u can cancel out
ganeshie8 (ganeshie8):
that gives u
\(\large -2xy^2 + 1\)
OpenStudy (anonymous):
So why did the 12x^2y^4 turn into -2xy^2 + 1 ?
OpenStudy (anonymous):
Anyway thank you :)
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
good question :)
ganeshie8 (ganeshie8):
\(\large \frac{−12x^3y^4 + 6x^2y^2}{6x^2y^2}\)
ganeshie8 (ganeshie8):
before cenceling, u need to take GCF of numerator
ganeshie8 (ganeshie8):
u cannot cancel the second term and denominator directly okay ?
ganeshie8 (ganeshie8):
GCF of numerator is \(6x^2y^2\)
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
when u pull it from numerator's first term, \(-12x^3y^4\),
it leaves \(-2xy^2\)
ganeshie8 (ganeshie8):
\(\large -12x^3y^4 = 6x^2y^2(-2xy^2)\)
OpenStudy (anonymous):
ooooh I got it, I forgot about that.
OpenStudy (anonymous):
Thanks again.
ganeshie8 (ganeshie8):
good to hear :) u wlc :)