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Mathematics 20 Online
OpenStudy (anonymous):

What are the coordinates of the image of -3, 2 when the point is reflected across the line ? y=4 please just give me the answer

OpenStudy (anonymous):

|dw:1394822665594:dw|

OpenStudy (anonymous):

Thank you!!!!!!!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

Wait that's not one of the answers

OpenStudy (anonymous):

A -1,6 b -3,6 c -3,4 b 6,-3

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

i see b

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

could you help me with something else?

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

i will try.

OpenStudy (anonymous):

Translate the triangle with A (3, 4) B (2, -1) and C (4, 12) along the vector (-1, 3) Find the coordinates of the new image.

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

do you know the answer? :)

OpenStudy (anonymous):

Slope of line PQ=3/-1=-3 |dw:1394824009254:dw| Slope of any line perpendicular to line PQ=-1/-3=1/3 eq. of line PQ is y-3=-3(x+1) or y=-3x ...(1) eq. of any line perpendicular to PQ through (4,12) is y-12=1/3 (x-4) 3y-36=x-4 or 3y-x=36-4=32 ...(2) because it cuts line (1) 3(-3x)-x=32 -9x-x=32 x=-3.2 y=-3x=-3*-3.2=9.6 point of intersection is (-3.2,9.6) let (x1,y1) be the image of C. then \[\frac{ x1+4 }{ 2 }=-3.2,x1=-3.2*2-4=-6.4-4=-10.4\] \[\frac{ y1+12 }{ 2 }=9.6,y1=2*9.6-12=19.2-12=7.2\] therefore C' is (-10.4,7.2) similarly try for A' and B'

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