Question

Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64?

Answer 1

@Nurali

Answer 2

if the value that makes x-8 = 0 makes the f(x) = 0 .. then yes

Answer 3

Yes. When the function f(x) = –2x3 + 17x2 – 64 is divided by x – 8, the remainder is zero. Therefore, x – 8 is a factor of f(x) = –2x3 + 17x2 – 64.

Answer 4

a. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64.
OR
c. Yes. When the function f(x) = -2x3 + 17x2 - 64 is divided by x - 8, the remainder is not zero. Therefore, x - 8 is a factor of f(x) = -2x3 + 17x2 - 64.

Answer 5

\[\frac{(x-c)~Q(x)}{(x-c)}\]
\[\frac{(c-c)~Q(c)}{(c-c)}=\frac 00\]