Question

Pleas help

Answer 1

You're going to be using the formula: \[Q = (m)(c)(\Delta T)\]

Answer 2

Q - heat in joules
343 cal; but you want that in joules so you're going to have to convert
How many joules are in a calorie? 4.1858 J = 1 cal
You're going to want to multiply, (343 cal) by (4.1858 J) = 1435.7294 J

m - mass in grams
55.0 g of Cu (that's great you don't have to convert anything)

c - specific heat
this is what you're looking for so this would be your x - value

delta t - change in temperature (K or C)
19.0 degrees C to 86.0 degrees C
final temp minus initial temp (86.0 - 19.0) = 67 degrees C

Now that you have all your values, you're going to want to plug them into the equation!

Answer 3

can you show me that also, please?

Answer 4

like this? Q = 55.0 * 67 degrees C * 1435.7294 J

Answer 5

Not quite, the Q = is the unit of Joules
You're looking for specific heat (c value) not the (Q value)

Answer 6

1435.7294 J = (55 grams)(x)(67 degrees C)
Multiply 55 by 67 and you get 3685.
Then divide 1435.7294 by (3685) and you should get the specific heat of copper.

Answer 7

Show me please. I got only two more minutes D: this is the only one I was stuck on

Answer 8

As a result, I got 0.3896 which I then rounded to 0.39

Answer 9

So the specific heat then would be 0.39 for Copper.

Answer 10

39 degrees?

Answer 11

Wait, no what.
You're looking for the specific heat not temperature.... Are you asking what the unit for the C of Copper?

Answer 12

what is the specific heat for copper. isn't .39? D;

Answer 13

I hope it's right, cuz my times is over. Thank you so much for explaining it step by step <3

Answer 14

No the specific heat of copper is .39. It's just not .39 DEGREES. The unit you used was wrong but the answer is .39

Answer 15

OH yay i didnt put degrees. I was about to though. (thank god) c; Haha THANKS!