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OpenStudy (luigi0210):
When something is raised to a power, multiply the powers. And a negative exponent, flip it.
\[\Huge (a^x)^y=a^{x*y}\]
\[\LARGE x^{-a}=\frac{1}{x^a}\]
OpenStudy (anonymous):
I don't really understand what you're saying.
OpenStudy (whpalmer4):
\[(3y)^4*y^{-2}\]Let's work the \((3y)^4\) part first. Do you know that \((ab)^n = a^n*b^n\)?
OpenStudy (luigi0210):
\[\LARGE (3y)^4=3^{1*4}(y^{1*4})\]
OpenStudy (anonymous):
So it would be \[3^{4}*y ^{4}\] for the first part
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OpenStudy (whpalmer4):
Yes. And when you multiply two items having exponents and the same base, such as \(y^4*y^{-2}\) you keep the base and add the exponents: \(a^m*a^n = a^{m+n}\)
OpenStudy (anonymous):
Okay so what should I do next??
OpenStudy (anonymous):
Okay I'm pretty sure the answer is 3y^2. Can anyone verify this?
OpenStudy (whpalmer4):
No, it's not. \(3^4*y^4*y^{-2} = 3^4*y^{4-2} = \)
OpenStudy (luigi0210):
My mistake, sorry xD
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OpenStudy (whpalmer4):
@lasoftballchic101 what's your new, corrected answer?