solve the linear system x+3y=2 and 3x+9y=6 The answer is (2-3k,k) I realize you have to multiple the 1st equation by 3 and when you do so you get the identical equation to the second one. Thus when you subtract, you get 0+0=0 which means they have an infinite of solutions but how do I get the answer?
3x + 9y = 6 reduces to x + 3y = 2 this does match your other equation making them on the same line with infinite solutions. (2 - 3k,k) makes no sense. Your answer should be INFINITE SOLUTIONS. Unless you are supposed to sub in 2 - 3k in for x and k in for y ??
It does make sense when you let Y=k and the substitute that into either equations to get the x value that's my rationale
Thanks for trying
even if you sub that in, that is just 1 solution...there are infinitely many more
Idk vectors and calculus is an odd class
If you need me to sub it in and solve for k, I can do that
No it's okay I figured it out
cool :)
Oh btw if k is a set of teal numbers k can be anything and you'll get an infinite amount of solutions
Real*
correct :)
Join our real-time social learning platform and learn together with your friends!