Question

using property of exponents, solve 32^t+1 = 16^1-t

Answer 1

i guess it is
\[\large 32^{t+1}=16^{1-t}. \]

Replace 32=2^5 and 16=2^4. Then do some algebra (exponents' laws), u will get
\[\large 2^A=2^B \]
and from this u imply A=B.

Answer 2

to continue
2^5(t+1) = 2^4(1-t)
therefore 5(t + 1) = 4(1-t)
5t + 4t = 4 -5

Answer 3

thank you, I got!

Answer 4

you are welcome