Question

plz help

Answer 1

Hmm first one looks correct :)

Answer 2

ok

Answer 3

If you remember your perfect squares, it'll help a lot on these problems.
\[\Large\bf\sf \sqrt{64}=8\]\[\Large\bf\sf \sqrt{81}=9\]\[\Large\bf\sf \sqrt{100=10}\]Can you use this information to figure out the second problem?

Answer 4

Ahh typo on that last one :( my bad.\[\Large\bf\sf \sqrt{100}=10\]

Answer 5

no prob thx for the help :)

Answer 6

\[\Large\bf\sf \sqrt{121}=11\]This should help us figure out the third one :)

Answer 7

For the fourth one,\[\Large\bf\sf \sqrt{19}\quad=\quad \sqrt{16+3}\quad=\quad \sqrt{16\left(1+\frac{3}{16}\right)}\]
\[\Large\bf\sf \sqrt{16\left(1.1875\right)}\quad=\quad 4\sqrt{1.1875}\]So it's clearly 4 and some remainder.
You don't have to be this thorough, it's just another way to look at it.

It might be easier just to say,
4=sqrt(16)
5=sqrt(25)

So it has to be 4.something.

Answer 8

Are you allowed to use a calculator on these? :o

Answer 9

yes

Answer 10

can you show me the equation to solve the last question

Answer 11

Well you can input it directly into your calculator.
That would be the easiest method.

Do you mean equation like I did for problem 4?

Answer 12

yes

Answer 13

We can write 75 so it's a perfect square plus some remainder,\[\Large\bf\sf \sqrt{75}\quad=\quad \sqrt{64+11}\]Then we'll factor out 64 from each term,
\[\Large\bf\sf \sqrt{64\left(1+\frac{11}{64}\right)}\]We'll rewrite 1+11/64 as a decimal,\[\Large\bf\sf \sqrt{64(1.171875)}\]We can take the square root of 64,\[\Large\bf\sf =8\sqrt{1.171875}\]But then at this step you have to use a calculator.. which is what we could have done at the start anyway :(
Hmm

Answer 14

im sorry that you had to type all that but it seems more easy that way

Answer 15

Which way seems easier?
Hopefully you mean the calculator way :)

\[\Large\bf\sf \sqrt{75}\quad\approx\quad 8.660254\]Then just round from there, right?

Answer 16

thanks for the help i got a 100 on the test :3

Answer 17

yay \c:/