Question

*Can anyone explain how to do this?* A cyclist rides her bike at a rate of 12 meters per second. What is this rate in kilometers per hour? How many kilometers will the cyclist travel in 4 hours?

Answer 1

You need to first find out how much seconds are in a minute so 60. times 12x60 and you will have one minute. Times that number by 60 to get one hour. Time that one hour by 4 to get you total of hoe much she rides in 4 hours.

Answer 2

*how

Answer 3

Do you need the answer

Answer 4

That would be meters per hour

Answer 5

Oh well, just convert those meters in kilometers and thats your answer

Answer 6

For every 1000m, it is 1 kilometer

Answer 7

Example, 1200m, would be 1.2 kilometers

Answer 8

:O, what happened to my medal?!?

Answer 9

I took it back because palmer is about to unload an information bomb on us all

Answer 10

I'm waiting for whpalmer's response. I would like to know what it is.

Answer 11

12 m/s * s/m * m/hr
\[1 \text{ minute} = 60 \text{ seconds}\]Divide both sides by 1 minute:
\[1 = \frac{60 \text{ seconds}}{1 \text{ minute}}\]
\[1 \text{ hour} = 60 \text{ minutes}\]Divide both sides by 1 hour:
\[1 = \frac{60 \text{ minutes}}{1 \text{ hour}}\]
\[1 \text{ kilometer} = 1000 \text{ meters}\]Divide both sides by 1000 meters:
\[1 = \frac{1 \text{ kilometer}}{1000 \text{ meters}}\]
You can multiply anything by 1 without changing its value, so we'll multiply
\[12 \frac{\text{ meters}}{\text{ second}} * \frac{60 \text{ minutes}}{1 \text{ hour}} * \frac{ 60 \text{ seconds}} {1 \text{ minute}}\frac{1 \text{ kilometer}}{1000 \text{ meters}} = \]\[12 \frac{\cancel{\text{ meters}}}{\cancel{\text{ second}}} * \frac{60 \cancel{\text{ minutes}}}{1 \text{ hour}} * \frac{ 60 \cancel{\text{ seconds}}} {1 \cancel{\text{ minute}}}* \frac{1 \text{ kilometer}}{1000 \cancel{\text{ meters}}}\]\[= \text{_______ kilometers/hour}\]

Answer 12

If you do your conversions like this, you get built-in error checking. If the units don't cancel properly, you've set up the conversion wrong.

Answer 13

It's a bit more writing, but so is having to do the problem over because you muffed the unit conversion :-)

Answer 14

Oh, wow. Thank you (: I had originally thought the question was missing information, but you certainly helped whpalmer.

Answer 15

Great! You're the lucky winner of my last helping effort for the evening, time to go to rehearsal :-)