Question

Find an equation for the line parallel to
2x-3y+6=0, with the same y-intercept as y=7x-1

Answer 1

Step 1: What is the y intercept of y = 7x -1 ?

Answer 2

-1 ?

Answer 3

Yes... So the coordinates of that y-intercept is (0,-1). Does that make sense?

Answer 4

yes

Answer 5

So our equation will have to go through that point.
Now we just need to find the slope of our line.
Our line will need to be parallel to 2x-3y+6=0
If it is gonna be parallel to that it needs to have the same slope as that.
So....what is the slope of 2x-3y+6=0 ?

Answer 6

2 ?

Answer 7

2/3?

Answer 8

No.
To find the slope of that...put it in the form y = mx + b
2x - 3y + 6=0
2x - 3y =- 6
-3y = -2x - 6 .....now divide both sides by -3
y = 2/3 x + 2
So what's the slope ?

Answer 9

yeah...made a small irrelevant mistake
Slope is 2/3

Answer 10

If we know a point on the line (0,1) and the slope...
we can use the point slope form
y - y1 = m(x - x1) x1 is 0 y1 is 1 m is 2/3 Plug all that in and you have your equation

Answer 11

how do i figure that out?

Answer 12

@BangkokGarrett ^^

Answer 13

the formula that I was taught is: y=m(x-p)+q

Answer 14

Just plug in everything
y - y1 = m(x - x1)
y - 1 = 2/3(x - 0)
y - 1 = 2/3 x
y = 2/3 x + 1

Answer 15

ohhh okay i see

Answer 16

ok...your formula is basically the same as mine...just arranged slightly differently