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ganeshie8 (ganeshie8):
thats the final simplified expression
ganeshie8 (ganeshie8):
see if that looks okay
ganeshie8 (ganeshie8):
next, think about part b
OpenStudy (sanra123):
oh thanks now i knew why 1/2
ganeshie8 (ganeshie8):
good :)
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OpenStudy (sanra123):
we start multiplying the answer and see if we get the expression
OpenStudy (sanra123):
@ganeshie8
OpenStudy (sanra123):
area of triangle = 1/2 (4x-4)(2x-2)
hi sorry but how did u to this for the triangle ?
ganeshie8 (ganeshie8):
area of triangle = 1/2(b)(h)
OpenStudy (sanra123):
isn't the answer have to be
(16+4) (x-1)
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OpenStudy (sanra123):
@ganeshie8
ganeshie8 (ganeshie8):
how ?
ganeshie8 (ganeshie8):
we're done wid part a right ?
OpenStudy (sanra123):
by grouping
ganeshie8 (ganeshie8):
it shoudl be (16+4)(x-1)^2 okay ?
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ganeshie8 (ganeshie8):
when u add u wud get :
20(x-1)^2
ganeshie8 (ganeshie8):
thats for part a
OpenStudy (sanra123):
oh ok...
OpenStudy (sanra123):
ya now part be we will be checking how is it the right answer
OpenStudy (sanra123):
b
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ganeshie8 (ganeshie8):
for part b, u may do below :-
plugin x = 2,
and see wat u get for area using the simplified formula : 20(x-1)^2
ganeshie8 (ganeshie8):
next,
when x = 2, find out area of square and triangle separately. and add them.
ganeshie8 (ganeshie8):
u should get the same answer by using both mehtods..
ganeshie8 (ganeshie8):
Area of pentagon using simplified formula, when x = 2 :-
A = 20(2-1)^2 = 20
OpenStudy (sanra123):
why =20
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ganeshie8 (ganeshie8):
Area of square = (4*2-4)(4*2-4) = (4)(4) = 16
Area of triangle = 1/2(4*2-4)(2*2-2) = 1/2(4)(2) = 4
adding them gives : 16+4 = 20
so we just verified that the formula is correct for x = 2
OpenStudy (sanra123):
how did u solve for square
ganeshie8 (ganeshie8):
Area of square = (4x-4)(4x-4)
ganeshie8 (ganeshie8):
plugin x = 2 above
OpenStudy (sanra123):
4(2)-4 4(2)-4
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OpenStudy (sanra123):
then here how do we get 16
ganeshie8 (ganeshie8):
whats 4(2) - 4 ?
OpenStudy (sanra123):
4
ganeshie8 (ganeshie8):
yes
OpenStudy (sanra123):
then 4*4 =16
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ganeshie8 (ganeshie8):
yup
OpenStudy (sanra123):
then with the triangle im confused in solving it
ganeshie8 (ganeshie8):
write down Area of triangle formula first
OpenStudy (sanra123):
1/2(4*2-4)(2*2-2)
ganeshie8 (ganeshie8):
Area of triangle = 1/2(4x-4)(2x-2)
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ganeshie8 (ganeshie8):
plugin x = 2
OpenStudy (sanra123):
1/2 4(2)-4 2 (2)-2
OpenStudy (sanra123):
@ganeshie8
ganeshie8 (ganeshie8):
yes, simplify it
ganeshie8 (ganeshie8):
1/2 [4(2)-4 ] [2 (2)-2]
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OpenStudy (sanra123):
4 +2
ganeshie8 (ganeshie8):
nope,
1/2 [4(2)-4 ] [2 (2)-2]
first u need to work the thing inside parenthesis
ganeshie8 (ganeshie8):
1/2 [4(2)-4 ] [2 (2)-2]
^^^^^ ^^^^^
OpenStudy (sanra123):
oh ok
ganeshie8 (ganeshie8):
1/2[8 - 4] [4 - 2]
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ganeshie8 (ganeshie8):
1/2[4] [2]
ganeshie8 (ganeshie8):
4
OpenStudy (sanra123):
ohh ok
OpenStudy (sanra123):
lets do c
OpenStudy (sanra123):
@ganeshie8
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ganeshie8 (ganeshie8):
for part c,
start by writing out the area of triangle formula again
ganeshie8 (ganeshie8):
Area of triangle = \(\large \frac{1}{2}(4x-4)(2x-2)\)