Question

Solve the linear system: x+2y-z=0
-3x-6y+3z=0
2x+4y-2z=0

I realize that once you elminate (1) and (2), it equates to 0=0 and the same when you elminate (2) and (3) which means there are an infinite of solutions. However, the answer is (-2k+l,k,l),k,l are a set of real numbers.

Answer 1

x=-2k+l, y=k, and, l=z

Answer 2

alright i figured it out...
since there is an infinite of solutions but we need and x,y,z coordinate. if you let l=z, and y=k, and substitute this into one equation you will get the x value.

Answer 3

thanks for trying