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Mathematics 14 Online
OpenStudy (anonymous):

Solve the linear system: x+2y-z=0 -3x-6y+3z=0 2x+4y-2z=0 I realize that once you elminate (1) and (2), it equates to 0=0 and the same when you elminate (2) and (3) which means there are an infinite of solutions. However, the answer is (-2k+l,k,l),k,l are a set of real numbers.

OpenStudy (anonymous):

x=-2k+l, y=k, and, l=z

OpenStudy (anonymous):

alright i figured it out... since there is an infinite of solutions but we need and x,y,z coordinate. if you let l=z, and y=k, and substitute this into one equation you will get the x value.

OpenStudy (anonymous):

thanks for trying

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