Factor: question below Help I will fan and medal
\[2x^2 + 11x +12=0\]
you need two numbers whose product is 12 and to get the +11 one of these numbers multiplied by 2 plus other number will give 11
if these 2 numbers are a and b the factors will be (2x + a)(x + b)
2a + b = 11 ab = 12
Hey! I can help you solve your question if you'd like :)
solve these for a and b
its a very simple question, are you in grade 9?
ya
@cwrw238 thanks
yw
I cant find what a and b would equal
Factoring 2x2+11x+12 The first term is, 2x2 its coefficient is 2 . The middle term is, +11x its coefficient is 2 . The last term, "the constant", is +12 Step-1 : Multiply the coefficient of the first term by the constant 2 • 12 = 24 Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 8 2x2 + 3x + 8x + 12 Step-4 : Add up the first 2 terms, pulling out like factors : x • (2x+3) Add up the last 2 terms, pulling out common factors : 4 • (2x+3) Now add up the four terms of step 3 : (x+4) • (2x+3) Equation at the end of step 1 : (2x + 3) • (x + 4) = 0 Solving a Single Variable Equation : Solve : 2x+3 = 0 Subtract 3 from both sides of the equation : 2x = -3 Divide both sides of the equation by 2: x = -3/2 Solving a Single Variable Equation : Solve : x+4 = 0 Subtract 4 from both sides of the equation : x = -4 So your solutions x= -3/2 x=-4 Hope this helps :)
Sorry, long post :)
Did that help @SnowCrystal any q's ?
nope that helped a ton thank u soooo much
Join our real-time social learning platform and learn together with your friends!