Question

the equation of the line tangent to y=2secx at ax=pi/4 is ?

Answer 1

ok so the next step is this y=2sec(pi/4)tan(pi/4), right???

Answer 2

you mean
\(\large y'|_{x=\pi/4} = 2\sec (\pi/4)\tan (\pi/4)\)

then yes, you're correct.
and that will give you slope = m

Answer 3

is the slope 2 ?? cuz thats whats i get

Answer 4

not actually,
sec pi/2 is sqrt 2

Answer 5

***sec pi/4 = sqrt 2

Answer 6

(2/