Someone PLEASE help me add and simplify this. I did it myself but I got a wrong answer apparently.

log2 4 + log2 16

Question

Someone PLEASE help me add and simplify this. I did it myself but I got a wrong answer apparently. 

log2 4 + log2 16

awesome781 · Answer

You would use the product property...since they have the same base.... you would multiply 4 by 16

awesome781 · Answer

You understand what I'm saying right?

anonymous · Answer

Yes I did that but I am doing a review sheet and it is multiple choice and that is not one of the answers

anonymous · Answer

A)8
B)4
C)10
D)6
These are the answers

timaashorty · Answer

he/she didn't give you the answers yet.

timaashorty · Answer

By the way , it's D. 6

anonymous · Answer

Well I guess I am asking how you simplify it, I thought the answer would be log2 64

mrnood · Answer

you are correct - this is similar to what we did just now.

If you ADD logs that is equivalent to Multiplying numbers

so log 4 + log 16 = log 64  (it doesn't matter what the base of the logs is)

BUT the meaning of a log is(assuming base 2 in this case)

$$2^{logx}=x$$

So we have $$2^{logx}= 64$$

If you know your binary numbers you will be able to see that logx must be 6

You were right - but just missed the last step

anonymous · Answer

Thank you so much that helps me understand a lot better !