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Solve the differential equation
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\[y'(t)-2e^t \int\limits_{0}^{t}e^{-\xi}y(\xi )d \xi =t\]
y(0)=2
I know this requires convolution integrals but that integral term is bothering me.
It's a function times an integral. How would I even deal with that? :/ .
I want to say the e^(t) function does not include the variable which is used in the integration so it can be taken into and out of the integrand freely.
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But then we have three terms inside that integral :/ .
Well \( e^{-\xi} e^{t} y(\xi) d \xi \) = \( e^{t - \xi} y(\xi) d \xi \) by the property of multiplying like-bases.
yep I see that.
that is then the definition of a convolution, correct?
Ooo!!! How did I not see that? >.< . Thanks!
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You're welcome! :D
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