Volume of a balloon. The volume V(in cubic meters) of a hot air balloon is given by v(r)=4/3πr^3. If the radius r is increasing with time t (in seconds) according to the formula r(t)= 2/3t^3, t≥0 find the volume V as a function of the time t.
I believe you replace r in v(r) with r(t). V(t)=4/3(pi)(2/3t^3)^3
Expand out (2/3t^3)^3 and simplify.
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@whpalmer4 can you help?
What do you think you should do given the provided information?
I have no clue =(
so far i have (2/3)^3 t^9
Ok, so you want that in terms of t
ok...holy crud im horrible at this stuff.. explain how please =(
Alright. So you have r(t). In other words, the function of t. Your volume requires a radius or r. Since r is already defined, you must substitute r into the volume equation. Try it :)
@OrthodoxMan It's the algebra, I think
v(t)= 4/3π[(2/3)t^3]^3 = (2/3)^3 t^9 ?
You forgot the initial constant
Initial constant: 4/3 pi
v= 4/3 π (8/27 t^9)
now simplify so it isn't so ugly looking (get rid of as many fractions as you can)
32/81πr^9
That looks right to me.
YAY!!!! =) thanks you guys! I dont know who to award...you all helped so much...
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