Question

Modulus of complex number z= (3+4j)/(-2+5j)?
Ive got to 14/29 - 23/29j then what?

Answer 1

Which then becomes \[\sqrt{\left( \frac{ 14 }{ 29} \right)^{2}+\left( \frac{ 23 }{ 29 } \right)^{2}}\]

Answer 2

\[\sqrt{\frac{ 725 }{ 841}}\]
Is this correct, and how do I simplify further?

Answer 3

I'm assuming you've simplified and multiplied correctly

Answer 4

Yes pretty good at that side of things.

Answer 5

Then that appears to be a good answer not further simp. now let me check it

Answer 6

Check with me?

Answer 7

So I'll type the tex commands, you tell me what to do ok?

Answer 8

yes ok

Answer 9

\[z= \frac{3+4i}{-2+5i}\]

Answer 10

ok now, how do I get rid of the complex on the bottom?

Answer 11

I'll show my working to where Im up to. Give me a sec.

Answer 12

it's cool just work with me

Answer 13

I'd prefer it ... I haven't solved it yet

Answer 14

\[\[\left( \frac{( 3+4j)(-2-5j }{ (-2+5j)(-2-5j} \right)\]\]
\[\frac{ -6-15j-8j-20j ^{2} }{ 4+10j-10j-25j ^{2} }\]
\[\frac{ 14-23j }{ 29 }\]

Answer 15

Ok, then I concur with your answer

Answer 16

As for simplify, just do prime decomposition I'd say

Answer 17

Its not simplified enough to be as per the multiple choice answers Im given.

Answer 18

decimal form? What are your choices?