Can someone please help me with Trig Identities?

sec^2x = (1-cos^2x)/(1-sin^2x) + csc^2x - cot^2x

Question

Can someone please help me with Trig Identities?

sec^2x = (1-cos^2x)/(1-sin^2x) + csc^2x - cot^2x

fibonaccichick666 · Answer

Can you elaborate please?

anonymous · Answer

So far I have:

$$\frac{  1}{ \cos ^{2} x} = \frac{ \sin ^{2}x }{ \cos ^{2}x } + \frac{ 1 }{ \sin^{2}x } - \frac{ \cos^{2}x }{ \sin^{2}x }$$

I'm stuck at this part.

fibonaccichick666 · Answer

ok so first don't change the left side at all otherwise the proof is a no go.
second sin/cos =what?

anonymous · Answer

Tangent

fibonaccichick666 · Answer

ok so what properties do you have about tan^2

anonymous · Answer

like tan^2x + 1 = sec^2x?

fibonaccichick666 · Answer

yup

fibonaccichick666 · Answer

but as a side note, are you sure this even works?

fibonaccichick666 · Answer

This page may help for ideas https://www.tcc.fl.edu/Current/Academics/LearningCommons/First%20Floor%20Documents/VerifyingTrigIdentities.pdf

anonymous · Answer

Oh, I get it now! By this, do you mean the whole equation and thank you very much!

fibonaccichick666 · Answer

oh wait a sec I see an easier way

fibonaccichick666 · Answer

Come back, that way was blah this is easy, just make them all into one fraction

anonymous · Answer

Oh I see! Thank you again!

fibonaccichick666 · Answer

ok np have a good one