A silversmith mixed 45 g of an 80% silver alloy with 50 g of a 25% silver alloy. What is the percent concentration of the resulting alloy? (Round your answer to one decimal place.)
@zepdrix if you're available can you help me out ty if so!
Hmmmm let's see if i can explain this in a way that makes sense D: These concentration problems always get me a bit tripped up.
`45 grams at 80% concentration` + `50 grams at 25% concentration` = `the 45 + 50 at some new concentration`. \[\Large\bf\sf 45\cdot 80\text{%}+50\cdot 25\text{%}\quad=\quad 95\cdot X\text{%}\]
We'll write our percents as decimals and try to solve for x.\[\Large\bf\sf 45\cdot0.8+50\cdot 0.25\quad=\quad 95\cdot \frac{x}{100}\]
Mmmm am I doing this right maybe? :d Is the first step kinda confusing?
i have everything like that except the last part (x/100) i have =95x
I have 0.8(45)+.25(50)=95x
Ummm ok that's fine. Just realize that your `x` that you end up with is not a percent. You'll need to convert it to a percent afterwards.
I though the answer was either 51 or 52% rounding but that is incorrect
51% was incorrect? D: Hmm
Oh one decimal, so we should get ummmm 51.1%
Maybe that will make a difference? :o
Thumbs up! TY!! @zepdrix
Oh was it that simple? :) yay team!
Join our real-time social learning platform and learn together with your friends!