Please, give me an example to illustrate this expression T is linear transformation on C Tz = az + comples conjugate (z)
why is everyone doing linear algebra today :/
@ikram002p if \(z = \alpha x + \beta i y \), then Tz = \(a(\alpha x+ \beta iy -\beta iy = a\alpha x\) @hba why not?
I have to prove/disprove it is invertible but not sure how to translate the question.
no idea?
sry was afk , ill check this :D
I appreciate your quickly response whenever I tag. :)
when z= ax+Biy conjugate (z)=ax-Biy so ur exampl Tz=a(ax+Biy)+(ax-Biy) Tz=(a^2+a)x + (aB-B) y
so , ok x , y still in linear mood a,b constant right ? then it work
but need to make sure that Tz is not = aax in the example u gave
I don't think a in Tz =a z is a in z = ax + bi y that's why I put z = \(\alpha x +\beta iy\) to make them separate
i see so u have a and alpha ?
well , it wont change it well still linear cuz x,y both linear exchange
Thanks for your explanation. I think I can work now. hihihi
good ! gtg now , good luck with the rest of it :D
:)
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