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OpenStudy (anonymous):
.
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OpenStudy (31356):
Sorry, we haven't learned about this in Chemistry class. o.0
OpenStudy (31356):
Sorry about that, I wish I can help though......
OpenStudy (31356):
Or you might ask @MelissaHolmes, she's good. :D
OpenStudy (31356):
However, she's not on now. o.0
OpenStudy (ipwnbunnies):
It seems right, but Idk if you're using the right gas constant. The kPa just disappears. :o
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OpenStudy (ipwnbunnies):
It might just be one of those units that can be derived from the units of the gas constant J/mol-K
OpenStudy (ipwnbunnies):
It can change depending on which units you use. For example, I use 0.08206 L-atm/mol-K most of the time.
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