Question

Can somebody please help me with an op-amp question? PLEASE!

Answer 1

Let \(v_{+}\) be the voltage at the positive terminal of the op-amp.
Then
$$
\large{
v_{+}=\cfrac{v_{out}\times 1.2k\Omega}{10.8k\Omega+1.2k\Omega}\\
v_{out}=\cfrac{v_{+}\times(10.8k\Omega+1.2k\Omega)}{1.2k\Omega}\\
=10v_{+}\\
}
$$
So, the voltage form is the same as the input and peaks at 20 volts, since the input peak is 2 V: