GRADE 10 QUADRATICS QUESTION: I have trouble with quadratics and need lots of help! The path of a soccer ball is modelled by the relation h= -1/16(d-28)^2+49, were d is the horizontal distance, in metres, after it was kicked, and h is the height, in metres, above the ground. A) sketch the path of the soccer ball B) what is the maximum height of the ball? C) what is the horizontal distance when this occurs? D) what is the height of the ball at a horizontal distance of 20m? E) find another horizontal distance where the height is the same as in part d).
so the formula is \[h= - \frac{ 1 }{ 16 }(d-28)^{2}+49\]
I honestly have no idea.
wolfman alpha will help just know how to type the problems in
what is that? @frankyp
http://www.wolframalpha.com/ it is a helpful site that helps with almost any questions
thank you i'lll try @frankyp
ok give me the problem you need help with
@frankyp yeah... i didn't understand the website
@tomhue PLEASE HELP ME
For A, sketch the graph using a graphing calculator or by plugging in points. For B, to find the maximum height, find the derivative and equate it to zero. For C, After getting d, plug it back in the original equation to get h again. For D, plug in 20 in the place of d. For E, find the derivative and equate it to h. Hope this helps.
but how do I find the points? what do I do?
let the x- axis be d and y be h. Btw which math class is this for?
That's a parabola (quadratic) in vertex form. Pretend d is x and h is y. \[y=-\frac{1}{16}(x-28)^2+49\] Remember, the form is y=a(x-h)^2+k. When a is negative, like in your equation, the graph will open downward. The variables h and k in there are the x and y coordinates of the vertex, which, since the graph opens downward, will be a minimum or maximum?
@boblovesmath this is for grade 10 academic math (like university level, not college)
minimum? i think?
@VrindaG I know but is it for algebra, calculus, precalculus?
so if i made a chart.. like one of those x and y charts, like this |dw:1394988619281:dw|
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