Question

Find all real solutions of (x^2 + 7)^3/2 = 64

Answer 1

taking square both sides equation becomes.

\[(x^{2}+7)^{3} = 64*64\]

now taking cube root

\[(x^{2}+7) = 4*4=16\]

\[x^{2}=9 \implies x=+3,-3\]

so solution of above equation are 3 and -3